Question

write the equation of the line, with the given properties, in slope-intercept form.Slope=-6, through (-8,8)

Answer 1

The given slope is:

`m=-6`

And the point:

`(-8,8)`

we label the coordinates as follows:

`\begin{gathered} x_1=-8 \\ y_1=8 \end{gathered}`

And now, we use the slope-point formula, which is:

`y-y_1=m(x-x_1)`

substituting the known values of slope m and the point:

`y-8=-6(x-(-8))`

We need to solve this for y to find the slope intercept form (which is y=mx+b):

`\begin{gathered} y-8=-6(x+8) \\ y-8=-6x-48 \\ y=-6x-48+8 \\ y=-6x-40 \end{gathered}`

The slope-intercept form is:

y = -6x - 40