Question

For the function f(x) = x^2 + 4, identify the values of f(0), f(1/2), and f(-1).

Answer 1

Step-by-step explanation:

The function is given below as

`f(x)=x^2+4`

Find

`\begin{gathered} f(0) \\ put\text{ }x=0 \\ f(0)=(0)^2+4 \\ f(0)=4 \end{gathered}`
`\begin{gathered} f((1)/(2)) \\ put\text{ }x=(1)/(2) \\ f((1)/(2))=((1)/(2))^2+4 \\ f((1)/(2))=(1)/(4)+4 \\ f((1)/(2))=(17)/(4) \end{gathered}`
`\begin{gathered} f(-1) \\ put\text{ }x=-1 \\ f(-1)=(-1)^2+4 \\ f(-1)=1+4 \\ f(-1)=5 \end{gathered}`

Hence,

The final answer is

`4,(17)/(4),5`

The FIRST OPTION is the correct answer