Question

what is the intermediate in the form (x+a)^2=b as a result of completing the square for the following equation?Answer:()^2=

Answer 1

Step 1: Write out the equation

`x^2-12x+32=4`

Step 2: Subtract 32 from both sides of the equation

`\begin{gathered} x^2-12x+32-32=4-32 \\ x^2-12x=-28 \end{gathered}`

Step 3: Complete the square by adding 1/2 of the square of the coefficient of x to both sides

That is

`x^2-12x+(-6)^2=-28+(-6)^2`

This implies that

`(x-6)^2=-28+36=8`

Hence the intermediate step is (x - 6)² = 8