Question

Calculate the moles of HCI needed to react completely with 8.25 moles of zinc. I picked C but I’m not sure if I’m correct

Answer 1

D. 16.5 moles

Step-by-step explanation:

From the balanced reaction we know that 1 mole of Zn reacts with 2 moles of HCl.

We can calculate the moles of HCl needed to react completely with 8.25 moles of zinc, using the stoichiometry of the reaction and a mathematical rule of three:

`\begin{gathered} 1moleZn-2molesHCl \\ 8.25molesZn-x=(8.25molesZn*2molesHCl)/(1moleZn) \\ x=16.5molesHCl \end{gathered}`

So, 16.5 moles of HCl are needed.