Question

Use substitution to solve.Solve the first equation for y and substitute it into the second equation. The resulting equati

Answer 1

The first equation is given as,

`\begin{gathered} 2X^2\text{ = 5 +Y} \\ Y\text{ = }2X^2\text{ - 5\_\_\_\_\_\_\_(1)} \end{gathered}`

The second equation is given as,

`4Y\text{ = }-20\text{ }+8X^2_{_{_{_{}}}}\text{ \_\_\_\_\_\_\_\_\_(2)}`

Substituting equation ( 1 ) in equation (2),

`4(\text{ }2X^2\text{ - 5) = }-20\text{ }+8X^2_{_{_{_{}}}}\text{ }`

Simplifying further,

`8X^2-20\text{ = -20 + }8X^2`

Thus the required answer is

`8X^2-20\text{ = -20 + }8X^2`