I just need answers. No need longer to explain.Solve a

Question

asked Apr 1, 2023 6.3k views

1 Answer

Chris Shao · Answer 1 · 2023-04-07T17:16:31+0000

We need to find the period of the sinusoidal function in this case we have the next form

$y=A\sin (2\pi)/(T)(x+a)+b$

First, we need to find the amplitude in this case

The amplitude is 3

Then we need to find the period

$T=(2\pi)/(3)$

and the the displacement b is 2

Then for a we have

$a=(5)/(12)\pi$

Therefore we have

$y=3\sin 3(x-(5\pi)/(12))+2$

ANSWER

$y=3\sin 3(x-(5\pi)/(12))+2$