Question

Please helpppppppppp - the diagram shows the trajectory of a ball that is thrown horizontally from a top of a building. The ball’s vertical and horizontal velocity vectors along with the resultant factors are also indicated if the ball takes three seconds to reach the ground how fast is it moving by the time it reached the ground

Answer 1

`\begin{gathered} t=3\text{ s} \\ g=9.81m/s^2 \\ v_y=\text{ (}9.81m/s^2\text{)(3s)} \\ v_y=\text{ 29.43 m/s} \\ v_x=1.9\text{ m/s} \\ v=√(v^2_y+v^2_x) \\ v=\sqrt{(\text{ 29.43 m/s})^2+(1.9\text{ m/s})^2} \\ v=29.49\text{ m/s} \\ \text{The velocity of the ball when it hits the ground is }29.49\text{ m/s} \end{gathered}`