Question

I will show you the question

Answer 1

The given system is

`\begin{cases}3x+6y=12 \\ x+2y=4\end{cases}`

First, we multiply the second equation by -3.

`\begin{cases}3x+6y=12 \\ -3x-6y=-12\end{cases}`

Then, we combine the equations

`\begin{gathered} 3x-3x+6y-6y=12-12 \\ 0=0 \end{gathered}`

This means the system has infinitely many solutions.

Hence, the answer is D.