Question

Logarithm 9) solve for P ( in terms of Q)Log (P - Q) = lop P - log Q

Answer 1

we have the expression

`\text{log (P}-Q)=\log P-\log Q`

Applying properties of log right side

`\text{log (P}-Q)=\log ((P)/(Q))`

Equate the numbers inside the parenthesis

`P-Q=(P)/(Q)_{}`

Solve for P

`P-(P)/(Q)=Q`
`P\lbrack1-(1)/(Q)\rbrack=Q`
`P=(Q)/(\lbrack1-(1)/(Q)\rbrack)`

Simplify

`P=(Q^2)/(Q-1)`