Question

3. In the figure below, XU is the midsegment of TVW and is parallel to VW, determine the length of XU. (3 points) 11x + 2 U 10x + 16

Answer 1

If XU is the midsegment of TVW, then, it is necessary that:

(11x + 2)/(10x + 16) = 1/2

multiply the previous equation by 10x + 16:

11x + 2 = 1/2(10x + 16)

11x + 2 = 5x + 8 subtract 5x and 2 both sides

11x - 5x = 8 - 2

6x = 6

x = 6/6

x = 1

THe length of XU is:

XU = 11x + 2 = 11(1) + 2

XU = 13