Question

-20k - 5) + 2k = 5k + 5A k = 0B) k = 4k = 1D) k = 2

Answer 1

The equation is:

`\begin{gathered} -2(k-5)+2k=5k+5 \\ \end{gathered}`

We can distribute the -2 into the parenthesis

`\begin{gathered} -2k+10+2k=5k+5 \\ 10=5k+5 \\ \end{gathered}`

now we solve for k

`\begin{gathered} 10-5=5k \\ 5=5k \\ (5)/(5)=k \\ 1=k \end{gathered}`