Question

I need help with the question

Answer 1

B

For this problem Let's work in parts

1) Coin

Heads

Tails

Flipping the coin once, the Probability is:

`P\text{ =}(1)/(2)`

For there are two possible results, Heads or Tails, and there was one flipping.

2) Spinner

1 to 6 sections

The Probability of this spinner lands on a number lesser than 3

`P\text{ =}(2)/(6)\text{ = }(1)/(3)`

is 1 out of 3 for this spinner, since only 1, 2 are valid results.

So, the answer to this experiment

`P\text{ = }(1)/(3)\cdot(1)/(2)\text{ = }(1)/(6)`

Is the probability of both happen, both spinner and coin are 1 in six flipping. Since there are only two numbers < 3 on the spinner and two possibilities for the coin.

B

Heads, 1

Tails 1

Heads2

Tails 2