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Time(wki469Height ofplant (in)9.013.520.25Find the rate of change for weeks 40le and 69.Explain the meaning of the rate of change for each case.

Time(wki469Height ofplant (in)9.013.520.25Find the rate of change for weeks 40le and-example-1

1 Answer

3 votes

\begin{gathered} slope_1=slope_2=2.25 \\ \end{gathered}

Step-by-step explanation

Step 1

when you have 2 coordinates ( A and B), the slope of the line that passes thought those point is given by


\text{slope}=(y_2-y_1)/(x_2-x_1)

where


\begin{gathered} A=(x_1,y_1) \\ B=(x_2,y_2) \end{gathered}

A and B are 2 known points of the line

Step 2

so, the slope represents the rate of change

i)the rate of change for 4-6 weeks

Let

A=(4 ,9)

B=(6,13.5)

replace


\begin{gathered} \text{slope}=(y_2-y_1)/(x_2-x_1) \\ slope_1=(13.5-9)/(6-4)=(4.5)/(2)=2.25 \\ slope_1=2.25 \end{gathered}

Step 3

ii)the rate of change for 6-9weeks

Let

A(6,13.5)

B(9,20.25)

replace,


\begin{gathered} \text{slope}=(y_2-y_1)/(x_2-x_1) \\ \text{slope}=(20.25-13.5)/(9-6)=(6.75)/(3)=2.25 \end{gathered}

the slope represents the rate of change, it means for every case the plant is growing at a constant rate (2.25 inches per week)

I hope this helps you

Time(wki469Height ofplant (in)9.013.520.25Find the rate of change for weeks 40le and-example-1
answered
User Pankaj Cheema
by
7.6k points
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