Question

Solve the equation. 42 = d2 - 22 d = and d =

Answer 1

we have

`42=d^2-22`

solve for d

`\begin{gathered} d^2=42+22 \\ d^2=64 \\ \text{square root both sides} \\ d=\pm\sqrt[]{64} \\ d=\pm8 \end{gathered}`

therefore

d=+8 and d=-8