Question

Rick shoots a basketball at an angle of 60' from the horizontal. It leaves his hands 6 feet from the ground with a velocity of 25 ft/s.Step 1 of 2: Construct a set of parametric equations describing the shot. Answer

Answer 1

Given:

`\begin{gathered} Initial\text{ velocity,}u=25ft\text{ /s} \\ \theta=60^0 \end{gathered}`

The parametric equations are gotten by first resolving the velocity into horizontal and vertical components.

Recall;

`\begin{gathered} speed=(distance)/(time) \\ distance=speed* time \end{gathered}`

Hence, the parametric equations are:

`\begin{gathered} x=(25cos60)t \\ y=(25sin60)t+6 \end{gathered}`