asked 15.7k views
0 votes
Can you please completely factor
11 {x}^(2) + 24x + 1320

asked
User Slecorne
by
8.8k points

1 Answer

4 votes

\begin{gathered} 11x^2+24+1320 \\ ax^2+bx+c=0 \\ \\ a=11\text{ b=24 and c=1320} \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-24\pm\sqrt[]{24^2^{}-4*11*1320}}{2*11} \\ \\ x=\frac{-24\pm\sqrt[]{576^{}-58080}}{22} \\ \\ x=\frac{-24\pm\sqrt[]{-57504}}{22} \\ x=\frac{-24\pm\sqrt[]{-57504}}{22} \\ x=(-24\pm i239.8)/(22) \\ \\ x=(-24+i239.8)/(22)\text{ or }x=(-24-i239.8)/(22) \\ (x+(24-i239.8)/(22))(x+(24+i239.8)/(22)) \end{gathered}

answered
User Wennie
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.