Question

Identify the roots of:y = x² - 12x + 32

Answer 1

Okay, here we have this:

Considering the provided function, we are going to calculate the requested roots, so we obtain the following:

`\begin{gathered} x^2-12x+32=0 \\ x_(1,2)=(-(-12)\pm√((-12^2)-4(1)(32)))/(2(1)) \\ x_(1,2)=(12\pm√(144-128))/(2) \\ x_(1,2)=(12\pm√(16))/(2) \\ x_(1,2)=(12\pm4)/(2) \\ x_(1,2)=6\pm2 \\ x_1=6+2,x_2=6-2 \\ x_1=8,x_2=4 \end{gathered}`

Finally we obtain that the roots of the function are x=8 and x=4.