asked 143k views
5 votes
Solve the system of equations. If the system has no solution, say that it is inconsistent.

Solve the system of equations. If the system has no solution, say that it is inconsistent-example-1
asked
User Sackling
by
7.4k points

1 Answer

4 votes

Answer:

D. The system is inconsistent

Explanation:

Given the below system of equations;


\begin{gathered} 2x-2y+5z=11\ldots\ldots\ldots\text{Equation 1} \\ 6x-5y+13z=30\ldots\ldots\ldots\text{.}\mathrm{}\text{Equation 2} \\ -2x+3y-7z=-13\ldots\ldots\ldots\text{Equation 3} \end{gathered}

We'll follow the below steps to solve the above system of equations;

Step 1: Add Equation 1 and Equation 3;


\begin{gathered} (2x-2x)+(-2y+3y)+(5z-7z)=(11-13) \\ y-2z=-2 \\ y=2z-2\ldots\ldots\text{.}\mathrm{}\text{Equation 4} \end{gathered}

Step 2: Multiply Equation 3 by 3, we'll have;


-6x+9y-21z=-39\ldots\ldots\text{.Equation 5}

Step 3: Add Equation 2 and Equation 5, we'll have;


4y-8z=-9\ldots\ldots\ldots\text{Equation 6}

Step 4: Put Equation 4 into Equation 6 and solve for z;


\begin{gathered} 4(2z-2)-8z=-9 \\ 8z-8-8z=-9 \\ 8z-8z=-9+8 \\ 0=-1 \end{gathered}

From the above, we can see that we do not have a solution for z, therefore, we can say that the system of equations has no solution, hence, it is inconsistent.

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.