Question

What is the center and radius for the circle with equation (x-2)^2 + (y-5)^2=49

Answer 1

For this case we have the following equation given by:

`(x-2)^2+(y-5)^2=49`

The general equation of a circle is given by:

`(x-h)^2+(y-k)^2=r^2`

And for this case by direct comparison we have:

`r^2=49`

Then we have:

`r=\sqrt[]{49}=7`

And the center si given by C=(h,k)

From the equation given we have:

`C=(2,5)`