Question

Solve the polynomial in standard form1) y=(x-3)^2-3(x-4)

Answer 1

`y=\mleft(x-3\mright)^2-3\mleft(x-4\mright)`
`\begin{gathered} y=x^2-6x+9-3x+12 \\ \end{gathered}`

we reduce the equal terms and we obtain the answer is

`y=x^2-9x+21`