Question

Find 5x3 + 2y2 - 9, where x = 4 and y = 2

Answer 1

`\begin{gathered} 5x^3+2y^2\text{ - 9} \\ \text{where } \\ x\text{ = 4} \\ y\text{ = 2} \end{gathered}`

The equation can be solved when we substitute the value of x and y accordingly .

`\begin{gathered} 5(4)^3+2(2)^2\text{ - 9} \\ 5\text{ }*\text{ 64 + 2 }*\text{ 4 - 9} \\ 320\text{ + 8 - 9} \\ =319 \end{gathered}`