Question

Solve you may use fraction circle pieces to help you you don’t really have to use

Answer 1

`\begin{gathered} a)(3)/(4) \\ b)(5)/(4) \\ c)(7)/(8) \\ d)(5)/(8) \end{gathered}`

1) Let's use the fraction circles then to solve this sum of fractions:

1) Note that since these fractions do not have the same denominator we can write out the following. Placing the LCM as the denominator\div

`\begin{gathered} a)(1)/(2)+(1)/(4)=(4/2*1+4/4*1)/(4)=(3)/(4) \\ b)LCM(2,4)=4 \\ (1)/(2)+(3)/(4)=(4/2*1)/(4)+(4/4*3)/(4)=(5)/(4) \\ c)\text{LCM(4,}8)=8 \\ (3)/(4)+(1)/(8)=(6+1)/(8)=(7)/(8) \\ d)\text{LCM(}4,8)=8 \\ (1)/(4)+(3)/(8)=(2+3)/(8)=(5)/(8) \end{gathered}`

Note that for 'c' and "d" we have made it faster. Since this is the same principle.