Question

Find the slope of the secant line for the g(x) = -20 SQRT x between x = 2 and x = 3

Answer 1

Given:

Equation of line is,

`g(x)=-20\sqrt[]{x}`

The slope of the secant line between x =a and x= b is calculated as,

`\begin{gathered} m=(f(b)-f(a))/(b-a) \\ m=(f(3)-f(2))/(3-2) \\ m=\frac{-20\sqrt[]{3}-(-20\sqrt[]{2})}{1} \\ m=-20\sqrt[]{3}+20\sqrt[]{2} \\ m=20(\sqrt[]{2}-\sqrt[]{3}) \\ m=-6.36 \end{gathered}`

Answer: slope of the secant line is m = -6.36