Question

Help me please. Im struggling and trying to pass the 12th grade

Answer 1

From a given right triangle,

We observe that,

`\begin{gathered} O\text{pposite side=6 cm} \\ \text{Adjacent side=6}\sqrt[]{3}cm \\ \text{Hypotenuous side=12cm} \end{gathered}`

Using the formula,

`\begin{gathered} \sin A=(opp)/(hyp) \\ \sin A=\frac{6\sqrt[]{3}}{12} \\ \sin A=\frac{\sqrt[]{3}}{2} \\ A=\sin ^(-1)(\frac{\sqrt[]{3}}{2}) \\ A=60^(\circ) \end{gathered}`

Using the formula,

`\begin{gathered} \sin B=(opp)/(hyp) \\ \sin B=(6)/(12) \\ \sin B=(1)/(2) \\ B=30^(\circ) \end{gathered}`

Hence, the answer is,

`A=60^(\circ),B=30^(\circ)`