Question

What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO.)?

Answer 1

`6.023\text{ x 10}^(23)\text{ molecules are present in 1 mole of CuSO}_4\text{ i.e. 159.5 g of CuSO}_4`

So, using unitary method

`3.36\text{ x 10}^(23)\text{ molecules will be there in }\frac{159.5}{6.023\text{ x 10}^(23)}\text{ x 3.36 x10}_{\placeholder{⬚}^{\placeholder{⬚}}}^(23)`
`=\text{ 88.97 g of CuSO}_4`