Question

Add 9∠30 and 12∠0Question 6 options:(18.19, 10.5)(19.79, 4.5)(21, 30)(7.79, 16.5)

Answer 1

Explanation:

When adding polar forms, it is best to convert them to rectangular forms.

`a\angle b=a\cos \theta+j\sin \theta`

Therefore:

`\begin{gathered} 9\angle30=9\cos 30+j\sin 30=4.5\sqrt[]{3}+0.5j \\ 12\angle0=12\cos 0+j\sin 0=1+0j \end{gathered}`

Adding the two results gives:

`\begin{gathered} 9\angle30+12\angle0=(4.5\sqrt[]{3}+0.5j)+1 \\ =(4.5\sqrt[]{3}+1)+0.5j \\ =8.794+0.5j \end{gathered}`

Finally, convert the result to polar form: