Question

Consider functions fand g.I + 122 + 41 – 12for 1 * 2 and r * -64.12A g(t) =16.1 + 1641 + 48for r # -123Which expression is equal to f(x) · g()O A.A.4781I + 6I – 2I + 6OC.D.I + 2I – 6

Answer 1

Given,

`\begin{gathered} f(x)=(x+12)/(x^2+4x-12) \\ g(x)=(4x^2-16x+16)/(4x+48) \end{gathered}`

To find the value of f(x) . g(x):

`\begin{gathered} f(x)* g(x)=(x+12)/(x^2+4x-12)*(4(x^2-4x+4))/(4(x+12)) \\ =(x^2-4x+4)/(x^2+4x-12) \\ =((x-2)(x-2))/((x-2)(x+6)) \\ =((x-2))/((x+6)) \end{gathered}`

Thus the solution is,

`f(x)\cdot g(x)=((x-2))/((x+6))`

The answer is option-c