Question

Select the two values of X that are roots of this equation.

Answer 1

The equation given is,

`x^2+3x-5=0`

Simplify

`\begin{gathered} Solve\text{ with the quadratic formula} \\ x_(1,\:2)=(-3\pm √(3^2-4\cdot \:1\cdot \left(-5\right)))/(2\cdot \:1) \\ x_(1,\:2)=(-3\pm √(29))/(2\cdot \:1) \\ \mathrm{Separate\:the\:solutions} \\ x_1=(-3+√(29))/(2\cdot \:1),\:x_2=(-3-√(29))/(2\cdot \:1) \\ x_1=(-3+√(29))/(2),\:x_2=(-3-√(29))/(2) \\ The\:solutions\:to\:the\:quadratic\:equation\:are: \\ x=(-3+√(29))/(2),\:x=(-3-√(29))/(2) \end{gathered}`

Hence, Option C and D are the correct answers.