Question

Find the applied voltage of a circuit that draws 0.2 amperes through a 4800-ohmresistance

Answer 1

• Current=I=0.2A
• Resistance=R=4800ohm

• Voltage =V

Using ohms law.

`\\ \sf\longmapsto (V)/(I)=R`

`\\ \sf\longmapsto V=IR`

`\\ \sf\longmapsto V=4800(0.2)`

`\\ \sf\longmapsto V=960V`

`\\ \sf\longmapsto V=0.96KV`