Question

What are the roots of this quadratic equation?-10.x2 + 12x – 9 = 0Ο Α.r=OB.ivo5+3iv24203iv6+10+ܩܙܗ ܕܐܗO C.ODm =2 3iv65ResetNext2021 Edmentum. All rights reserved.

Answer 1

For the general quadractic equation,

`ax^2+bx+c=0`

the roots are given by the quadratic formula,

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In our case,

`\begin{gathered} a=-10 \\ b=12 \\ c=-9 \end{gathered}`

Then, by substituting these values into the formula, we have

`x=\frac{-12\pm\sqrt[]{12^2-4(-10)(-9)}}{2(-10)}`

which gives

`\begin{gathered} x=\frac{-12\pm\sqrt[]{144^{}-360}}{-20} \\ x=\frac{-12\pm\sqrt[]{-216}}{-20} \\ x=(6)/(10)\pm\frac{6\sqrt[]{6}i}{-20} \end{gathered}`