Question

2. A capacitor has a capacitance of 1.50 x 10-10 F. How much charge is stored when the potential difference is 1.75 V?

Answer 1

The charge in a capacitor is given by:

`Q=CV`

plugging the values given we have that:

`\begin{gathered} Q=(1.5*10^(-10))(1.75) \\ Q=2.625*10^(-10) \end{gathered}`

Therefore the charge in the capacitor is:

`2.625*10^(-10)\text{ C}`