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2.3.g(x)r(x)a. g(2) =a. r(-1) =b. g|(x) = 3, x =b. r(x) = 4, x=c. g(0) =c. r(2) =

2.3.g(x)r(x)a. g(2) =a. r(-1) =b. g|(x) = 3, x =b. r(x) = 4, x=c. g(0) =c. r(2) =
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2.3.g(x)r(x)a. g(2) =a. r(-1) =b. g|(x) = 3, x =b. r(x) = 4, x=c. g(0) =c. r(2) =

2.3.g(x)r(x)a. g(2) =a. r(-1) =b. g|(x) = 3, x =b. r(x) = 4, x=c. g(0) =c. r(2) =-example-1
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User PerryW
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8.6k points

1 Answer

4 votes

We have the following:

1.

2.

2.3.g(x)r(x)a. g(2) =a. r(-1) =b. g|(x) = 3, x =b. r(x) = 4, x=c. g(0) =c. r(2) =-example-1
2.3.g(x)r(x)a. g(2) =a. r(-1) =b. g|(x) = 3, x =b. r(x) = 4, x=c. g(0) =c. r(2) =-example-2
answered
User Okkhoy
by
7.8k points
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