Question

0.8(10-x)=36 I understand just not fully

Answer 1

Step 1

Given;

`0.8(10-x)=36`

Required; To find the value of x

Step 2

Use the distributive law to expand the bracket

`a(b+c)=(a* b)+(a* c)`
`(0.8*10)+(0.8*(-x))=36`
`\begin{gathered} 8+(_{}-0.8x)=36 \\ Bring\text{ like terms together} \\ -0.8x=36-8 \\ -0.8x=28 \\ (-0.8x)/(-0.8)=(28)/(-0.8) \\ x=-35 \\ \end{gathered}`

Hence, the value of x = -35