Question

Really need help with number 16 just started learning this today and still don't quite understand would really appreciate the help

Answer 1

`x^2-(3)/(4)x+(1)/(8)=0`

0. To complete the square, it is easier to move the constants to the other side:

`x^2-(3)/(4)x+(1)/(8)-(1)/(8)=-(1)/(8)`
`x^2-(3)/(4)x=-(1)/(8)`

2. Getting the square of both sides:

`x^2-(3)/(4)x+(((3)/(4))/(2))^2^{}=-(1)/(8)+(((3)/(4))/(2))^2`
`x^2-(3)/(4)x+((3)/(8))^2=-(1)/(8)+((3)/(8))^2`
`x^2-(3)/(4)x+(9)/(64)^{}=-(1)/(8)+(9)/(64)`

3. Factoring and solving:

`(x^{}-(3)/(8))^2=(1)/(64)`
`(x^{}-(3)/(8))^2-(1)/(64)=(1)/(64)-(1)/(64)`
`(x^{}-(3)/(8))^2-(1)/(64)=0`

Answer:

`(x^{}-(3)/(8))^2-(1)/(64)=0`