Question

The electric field 0.500 m from acharge is 3370 N/C, pointing awayfrom the charge. What is thecharge? Include the sign of thecharge, + or -(The answer is *10^-8 C. Just fillin the number, not the power.)(Unit = C)

Answer 1

To solve this problem, we have to use the electric field definition.

`E=K\cdot(q)/(r^2)`

Replacing the needed information, we have

`3370=9*10^9\cdot(q)/((0.5)^2)`

Let's solve for q

`\begin{gathered} q=(3370\cdot0.25)/(9*10^9) \\ q=93.6*10^(-9)C \\ q=9.36*10^(-8)C \end{gathered}`

Therefore, the answer is 9.36*10^-8 C.