Question

Can you please help me with this trig ratios problem?

Answer 1

The expression is given

`\sin \theta=\frac{\sqrt[]{3}}{2}`

To determine the value of angle in degree.

`\theta=\sin ^(-1)(\frac{\sqrt[]{3}}{2})`
`\theta=60^(\circ)`

Hence the value of angle in degree is 60 degree.