Question

When a -3.72*10^-4 C chargemoves from point A to point B, itselectric potential energy increasesby 0.218 J. What is the potentialdifference between A and B?Include the correct sign, + or -.(Unit = V)

Answer 1

We know that the electrical potential formula is

`V=(PE)/(q)`

Replacing the given information, we have

`V=(0.218J)/(-3.72*10^(-4)C)\approx-586.02V`

Hence, the potential difference between A and B is -586.02 V.