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A tennis racket strikes a tennis ball with a force of 39 N. The racket is in contact with the ball for 0.21 seconds. What is the magnitude of the change in momentum of the tennis ball?

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User JaredL
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1 Answer

7 votes

Answer:

8.19 kg m/s

Step-by-step explanation:

The change in momentum is equal to the impulse. This impulse is also calculated as the force times time, so


\Delta p=F\cdot t

Then, replacing F = 39 N and t = 0.21 s, we get:


\Delta p=(39N)(0.21s)=8.19\text{ kg m/s}

So, the change in momentum of the tennis ball is 8.19 kg m/s

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User PatFromCanada
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