Hello, please help me with this geometry on circles and ratios.

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asked May 4, 2023 189k views

1 Answer

Reetika · Answer 1 · 2023-05-08T12:09:26+0000

To determine the tangent angle of a circle

$\begin{gathered} arcBDC\colon arcBC=3\colon2of360^0\text{ } \\ arc\text{ BDC = }(3)/(5)X360^0=216^0 \\ arc\text{ BC = }(2)/(5)x360^0=144^0 \end{gathered}$

Measure of angle A = 1/2 of arc BDC - arc BC

[tex]\begin{gathered} mHence the measure of angle 36°

Hello, please help me with this geometry on circles and ratios.-example-1

Hello, please help me with this geometry on circles and ratios.

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