Question

Given lines 1, m and n are all parallel and cut by two transversal lines, find the value of x. 11 m 33 6 n

Answer 1

In the given figure, lines l, m, and n are parallel.

These parallel lines are cut by two transversal lines proportionally.

So, we can set up the following proportion.

`(x)/(6)=(11)/(33)`

Let us solve for x.

`\begin{gathered} (x)/(6)=(11)/(33) \\ x=6\cdot(11)/(33) \\ x=2 \end{gathered}`

Therefore, the value of x is 2