asked 115k views
2 votes
What volume of 0.0105-M HBr solution is required to titrate 125 mL of a 0.0100-M Ca(OH) 2 solution?

1 Answer

4 votes

Step 1

In a titration, the next equation is used in the equivalence point:


M1\text{ x V1 = M2 x V2}

Where,

Number 1 will the conditions of HBr

Number 2 will the conditions of Ca(OH)2

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Step 2

Information provided:

M1 = 0.0105 M

V1 = unknown

---

M2 = 0.0100 M

V2 = 125 mL

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Step 3

Procedure:

From step 1, V1 is found as follows:


\begin{gathered} M1\text{ x V1 = M2 x V2} \\ V1\text{ = }\frac{M2\text{ x V2}}{M1} \\ V1\text{ = }\frac{0.0100\text{ M x 125 mL}}{0.0105\text{ M}}=\text{ 119 mL} \end{gathered}

Answer: V1 = 119 mL

answered
User Rob Kinyon
by
8.3k points
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