I am trying to solve for the missing side in a triangle. Trying to figure out whether to use cos,tan or sin.41 = x / 6 \sin(?)

Question

I am trying to solve for the missing side in a triangle. Trying to figure out whether to use cos,tan or sin.
`41 = x / 6 \sin(?)`

Answer 1

Triangle length = ?

Sin 41 = X/ 6•

then rewrite

X = 6• Sin 41 =

. = 6 • 0.65

. = 3.9

Then answer is

Missing side X = 3.9

.