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If y varies directly as x, and y = 6 when x = 3, find y whenx = 9. y = ?

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If y varies directly as x, we can write the following equation:


(y)/(x)=k

When x = 3, we have y = 6, so:


\begin{gathered} (6)/(3)=k \\ k=2 \end{gathered}

Now, using x = 9, we have:


\begin{gathered} (y)/(9)=2 \\ y=18 \end{gathered}

Therefore the answer is y = 18.

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User Blamdarot
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