Question

Find the area of the triangle below. Be sure to include the correct unit in your answer. 16yd 6yd 10yd

Answer 1

Consider the figure.

From the triangle ABD, we have,

`BD=\sqrt[]{16^2-6^2}=14.83`

Therefore,

`BC=14.83-10=4.83`

From the traingle ABC, we have,

`AC=\sqrt[]{4.83^2+6^2}=7.7`

Thus, the area of the traingle is,

`(1)/(2)*7.7*10=38.5`