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Do not round intermediate computations, and round your answer to the nearest hunderdth

Do not round intermediate computations, and round your answer to the nearest hunderdth-example-1
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User Wenqiang
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2 Answers

4 votes

Final answer:

When performing calculations, do not round off intermediate answers. Carry as many digits as possible from the intermediate answers to the next calculation step. Round off the final answer to the nearest hundredth.

Step-by-step explanation:

When performing calculations, it is important not to round off intermediate answers. Instead, you should carry as many digits as possible from the intermediate answers to the next calculation step. Round off the final answer to the nearest hundredth.

For example, let's say we have the calculation (13.2 + 12.252) x (1.35 x 2.1). We first add 13.2 and 12.252, which gives us 25.452. Then, we multiply this answer by 1.35 x 2.1, which equals 53.529. Finally, we round this answer to the nearest hundredth, which is 53.53.

answered
User Aref Karimi
by
8.4k points
1 vote

Given:

Principal = $2500

Rate = 7.5% per annum (compounded monthly)

Amount needed to constitute: $3000

To find:

Number of years

Step by step solution:


\begin{gathered} \text{ }A=p(1+(r)/((100)(12)))^(12n) \\ \\ 3000=2500(1+(7.5)/((100)(12)))^(12n) \\ \\ 1.2=(1.00625)^(12n) \\ \\ 1.2=(1.00625)^(12n) \\ \end{gathered}

We will use logarithm to solve the question furtherly:


\begin{gathered} ln(1.2)=12n[ln(1.00625)] \\ \\ n=(ln(1.2))/(12ln[1.00625]) \\ \\ n=\text{ 2.439 years} \end{gathered}

We can take it's value to approx 2 years 5 months.

answered
User Salsa
by
7.7k points

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