Question

Consider the line y=4/7x-7Find the equation of the line that is perpendicular to this line and passes through the point (7,2)Find the equation of the line that is parallel to this line and passes through the pint (7,2)What is the equation of the perpendicular line :What is the equation of the parallel line:

Answer 1

The general equation of line with slope m is express as :

y = mx + b

The given equation of line : y = 4/7x - 7

On comparing with the general form of line we get m = 4/7

Two lines are said to be perpendicular if the products of thier slope is (-1)

Let the slope of perpendicular line is n

So,

`\begin{gathered} mn=(-1) \\ (4)/(7)n=(-1) \\ n=(-1)*(7)/(4) \\ n=(-(7)/(4)) \end{gathered}`

So, the slope of perpendicular line is (-7/4)

The line is passing through (7,2)

Substitute them in the general equation of line:

y - 2 = (-7/4)(x-7)

So, equation of line is :

`y-2=((-7)/(4))(x-7)`