Question

If 28.5 mol of an ideal gas is at 4.89x10^5 Pa, what is the volume of the gas?

Answer 1

`\begin{equation*} 0.149\text{ }m^3 \end{equation*}`

Step-by-step explanation

Parameters given:

Amount of substance, n = 28.5 mol

Pressure of gas, P = 4.89 * 10⁵ Pa

Temperature of the gas, T = 35°C= 308.15 K

To find the volume of the gas, we have to apply the Ideal Gas law:

`PV=nRT`

where V = volume

R = Ideal gas constant = 8.314 m³Pa/Kmol

Therefore, solving for V, we have that the volume of the gas is:

`\begin{gathered} V=(nRT)/(P) \\ V=(28.5*8.314*308.15)/(4.89*10^5) \\ V=0.149\text{ }m^3 \end{gathered}`

That is the answer.