Question

Please help with this problem:Solve for b.16 = a^2 + b^2A. b = 16 − a2B. b = ±16−a^2−−−−−−√C. b = ±16+a^2−−−−−−√D. b = 4−a

Answer 1

We want to solve for b in the equation

`16=a^2+b^2`

Solving we have

`\begin{gathered} 16=a^2+b^2 \\ we\text{ will move a}^2\text{ to meet 16, we have } \\ 16-a^2=b^2 \\ b^2=16-a^2 \\ move\text{ the square to the other side, it becomes square root, we have } \\ b=\pm√(16-a^2) \end{gathered}`

Hence the answer is the second option