Question

8x10⁵ is how many times as great as 8x10 negative 1

Answer 1

Step-by-step explanation:

To find how many times is one number greater than another number we have to find the quotient between the two of them:

`(8*10^5)/(8*10^(-1))=(8)/(8)*(10^5)/(10^(-1))=10^(5-(-1))=10^(5+1)=10^6`

Answer:

8x10⁵ is 10⁶ times greater than 8x10⁻¹