Question

A guitar player tunes her strings so thatthere is a beat frequency of 4.0 Hzbetween them. If one string has afrequency of 988 Hz, what is thefrequency of the other string? (Thereare two possible answers; give one.)(Unit Hz)

Answer 1

F beats = 4 HZ

F1 = 988 HZ

F beats = F1 - F2 ( or Fb = F2 - F1)

Replacing:

4 = 988 - F2

F2 = 988 - 4

F2 = 984 Hz